21[x-(2x+4)+3]=2(x+1)

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Solution for 21[x-(2x+4)+3]=2(x+1) equation:


Simplifying
21[x + -1(2x + 4) + 3] = 2(x + 1)

Reorder the terms:
21[x + -1(4 + 2x) + 3] = 2(x + 1)
21[x + (4 * -1 + 2x * -1) + 3] = 2(x + 1)
21[x + (-4 + -2x) + 3] = 2(x + 1)

Reorder the terms:
21[-4 + 3 + x + -2x] = 2(x + 1)

Combine like terms: -4 + 3 = -1
21[-1 + x + -2x] = 2(x + 1)

Combine like terms: x + -2x = -1x
21[-1 + -1x] = 2(x + 1)
[-1 * 21 + -1x * 21] = 2(x + 1)
[-21 + -21x] = 2(x + 1)

Reorder the terms:
-21 + -21x = 2(1 + x)
-21 + -21x = (1 * 2 + x * 2)
-21 + -21x = (2 + 2x)

Solving
-21 + -21x = 2 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-21 + -21x + -2x = 2 + 2x + -2x

Combine like terms: -21x + -2x = -23x
-21 + -23x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
-21 + -23x = 2 + 0
-21 + -23x = 2

Add '21' to each side of the equation.
-21 + 21 + -23x = 2 + 21

Combine like terms: -21 + 21 = 0
0 + -23x = 2 + 21
-23x = 2 + 21

Combine like terms: 2 + 21 = 23
-23x = 23

Divide each side by '-23'.
x = -1

Simplifying
x = -1

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